1. Normality may be equal but is always greater than the Molarity in the same solution.

2. If the valence is 1, Normality is equal to Molarity.

Try solving these problems. Atomic weights: Na = 23; Cl = 35.5, H = 1, Ca = 40, Valences: Ca = 2, NaCl = 1, HCl = 1.

**1. If you have dissolved 20 grams of sodium chloride in 1.5 Liter of distilled water, what is the:**

**1.1. Normality**

You have to remember that Normality is the Gram Equivalent Weight of substances. Hence, valence is involved. The formula would be:

N = W/GEW/Liter of solution

GEW = W/MW/valence

So, you have to solve first the MW (sum of atomic weights);

MW = 23 (Na) + 35.5 (Cl) = 58.5

Thus, substituting the values: GEW = 20/58.5/1

GEW = 0.3418803

N = GEW/Liter of solution

N = 0.3418803/1.5

**N = 0.2279202**

**Where:**

**N - Normality**

**W = weight of substance**

**GEW = Gram Equivalent Weight**

**MW = Molecular Weight**

**M = Molarity**

**1.2. Molarity**

Since you already know the Normality of the solution, you can make use of the short-cut formula, which is:

M = N/valence

Thus, substituting the values:

M = 0.2279202 x 1

**M = 0.2279202**

The answer is the same. This follows the rule: If the valence is 1, Normality is equivalent to Molarity.

**1.3. Percent solution**

You don’t usually need the molecular weights when solving percent solutions. You could use the general formula:

% = weight/total volume x 100

NOTE:

In solving for percent solutions, you have to convert the volume to milliliters. So,

1.5 Liters x 1000 mL/1 Liter = 1, 500 mL

Hence:

% = 20/1,500 x 100

**% = 1.33333%**

**2. What is the Molarity of 1 N Hydrochloric acid?**

Again in this problem, since you know the Normality, make use of the short-cut formula:

Thus:

M = N/valence

M = 1/1

**M = 1**

Again: If the valence is 1, Normality is equivalent to Molarity.

**3. What is the Normality of 0.8 M calcium chloride?**

Use the short-cut formula:

N = M x valence

N = 0.8 x 2

N = 1.6

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